Kip-sú

Chhai Sú-ho̍k chûng, yit-ke yû-khiùng fe̍t mò-khiùng ke sì-lie̍t$u_{0},u_{1},u_{2}\cdots$ ke Ngièn-su ke Hìn-sṳt-fò$S$ chhṳ̂n-vì Kip-sú (Mathematical Series). Sì-lie̍t $u_{0},u_{1},u_{2}\cdots$ chûng ke hong chhṳ̂n-chok kip-sú ke Thûng-hong . Kip-sú ke thûng-hong cho-tet he Sṳ̍t-sú, Kí-chhṳn fe̍t Hiong-liòng tén sòng-liòng, ya cho-tet he kôan-yî khì-thâ pien-liòng ke hâm-sú, put yit-thin he yit-chak sú. Ká-sṳ́ kip-sú ke thûng-hong he sòng-liòng, chet hâm-cho Sòng-sú hong Kip-sú , ká-sṳ́ kip-sú ke thûng-hong he hâm-sú, chet hâm-cho Hâm-sú hong kip-sú . Sòng-kien ke Kién-tân yû khiùng-sú-lie̍t ke kip-sú pâu-koat Tén-chhâ-sú-lie̍t fò Tén-pí-sú-lie̍t ke kip-sú.

$\sum _{n=1}^{\infty }{\frac {1}{2^{n}}}={\frac {1}{2}}+{\frac {1}{4}}+{\frac {1}{8}}+\cdots .$

$\sum _{n=0}^{\infty }a_{n}=a_{0}+a_{1}+a_{2}+\cdots$.